Difference between revisions of "20.109(F15):Battery assembly and testing (Day5)"

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(Introduction)
(Introduction)
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Today you will assess the data to determine how well your battery performed.  Previously, you prepared a battery electrode, specifically a cathode, from Fe(III)-phage nanowires that you combined with carbon.  The redox properties of this active material determine the operating voltage, while other properties influence the capacity (how long the battery 'lasts' under a given current load) and rate capability (how quickly the battery is discharged or charged).  Capacity and rate capability can be improved by making materials very small or by incorporating conductive metals into the matrix into the material.  The goal of your research is to assess how the amount of phage used in biomineralization affects capacity.
 
Today you will assess the data to determine how well your battery performed.  Previously, you prepared a battery electrode, specifically a cathode, from Fe(III)-phage nanowires that you combined with carbon.  The redox properties of this active material determine the operating voltage, while other properties influence the capacity (how long the battery 'lasts' under a given current load) and rate capability (how quickly the battery is discharged or charged).  Capacity and rate capability can be improved by making materials very small or by incorporating conductive metals into the matrix into the material.  The goal of your research is to assess how the amount of phage used in biomineralization affects capacity.
  
[[Image:Fa15 20.109 example capacity data plot.png|thumb|right|400 px|Plot illustrating how the of amount of phosphate influences capacity when phage quantity is held constant.]]
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The '''theoretical capacity''' of a battery is the quantity of electricity involved for the electro-chemical reaction within the battery. For our Fe(III)-phage batteries, the theoretical capacity is 178 mA*h/g, a value based on the cathode material - FePO<sub>4</sub>. Using this information, we can calculate the "'''loading factor'''" for the Galvanostat to be 54.9 mA/g (theoretical capacity divided by the time used to charge/discharge). This is the amount of current to use for a 10 hour discharge. The discharge time is selected by the researcherSlower discharge times are better as diffusion of the solvents is increased making it more likely that your battery will reach it's theoretical capacity.
The '''theoretical capacity''' of a battery is the quantity of electricity involved for the electro-chemical reaction within the battery. For our gold nanowire batteries, the theoretical capacity is 510 mA*h/g, a value based on the 15:4 Li:Au ratio and the phase diagram for a lithium-gold alloy. Thus, we can calculate the "'''loading factor'''" for the Galvanostat to be 51 mA/g (theoretical capacity divided by the time to charge/discharge). This tells us how much current to use for a 10 hour discharge. Similarly, it's also possible to calculate the needed current to fully charge or discharge your battery. The mass of every electrode will be a little different, so the charge/discharge rates will be slightly differentBut as an example, if one of the batteries has an electrode with precisely 1 mg of active material, then in order to discharge it in 10 hours we'd have to apply a negative current of -51 &mu;A.
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<br><center>1 mg x 510 mA*h/g x 1 g/1000 mg x 1/10 h = 51 &mu;A</center><br>
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[[Image:Charge-discharge.png|thumb|left|300px]]Take a look at your cell phone battery. If you have a typical LiCoO2 battery you will notice that it has a '''voltage''' (3.7 V) and a '''capacity''' (e.g. 710mA*h for the Motorola MOTORAZR V3r battery).  We know that LiCoO2 has a theoretical capacity of 130 mA*h/g, so it's possible to back calculate the amount of active material as 5.46 g (try it!).  The way Motorola determined the capacity and voltage for their cell phone batteries is by testing them on a Galvanostat.  This machine applies either positive or negative current in order to charge or discharge the batteries, identical to the protocol you will be following in lab today. By attaching any battery to a Galvanostat and applying a constant current (1100 mA), the battery will charge in a given time interval. By applying a negative current of 1100 mA it's possible to discharge the battery in that same amount of time. A discharge graph, such as the one shown here, plots voltage ''vs.'' capacity discharged. The flatter the curve the better, since this means voltage remains constant as the battery is used up. We will be testing every battery through 2 cycles of 10 hours each.
+
To calculate the current needed to fully charge or discharge your battery, you need to account for the mass of your cathode. The mass of every electrode will be a little different, so the charge/discharge rates will be slightly different.  But as an example, if your battery cathode is precisely 1 mg of active material, then to discharge it in 10 hours we'd have to apply a negative current of -54.9 &mu;A. 
 +
<br><center>1 mg active material x 178 mA*h/g x 1 g/1000 mg x 1/10 h = 54.9 &mu;A</center><br>
 +
It is important to remember note that your cathode consists of more than just the active material.  Remember that when you prepared your cathode material you used 70% Fe(III)-phage nanowires, 25% Super P, and 5% PTFE...in addition your Fe(III)-phage nanowires are ~10% phage.  To account for this, you need to adjust the weight of your cathode weight by multiplying by 0.63.  Be sure to know how this value was determined!
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[[Image:Fa15 20.109 example capacity data plot.png|thumb|right|400 px|Plot illustrating how the of amount of phosphate influences capacity when phage quantity is held constant.]]For a real world example, take a look at your cell phone battery. If you have a typical LiCoO<sub>2</sub> battery you will notice that it has a '''voltage''' (3.7 V) and a '''capacity''' (e.g. 710mA*h for the Motorola MOTORAZR V3r battery).  Given that LiCoO<sub>2</sub> has a theoretical capacity of 130 mA*h/g, it's possible to back calculate the amount of active material as 5.46 g (try it!).  Motorola determined the capacity and voltage for their cell phone batteries by testing them on a Galvanostat.  This machine applies either positive or negative current to charge or discharge the batteries, identical to the procedure used to test your battery. By attaching a battery to a Galvanostat and applying a constant current, the battery will charge in a given time interval. By applying a negative current it's possible to discharge the battery in that same amount of time. A discharge graph, such as the one shown here, plots voltage ''vs.'' capacity discharged. The flatter the curve the better, since this means voltage remains constant as the battery is used.
  
 
==Protocols==
 
==Protocols==

Revision as of 20:08, 1 December 2015


20.109(F15): Laboratory Fundamentals of Biological Engineering

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Introduction

Today you will assess the data to determine how well your battery performed. Previously, you prepared a battery electrode, specifically a cathode, from Fe(III)-phage nanowires that you combined with carbon. The redox properties of this active material determine the operating voltage, while other properties influence the capacity (how long the battery 'lasts' under a given current load) and rate capability (how quickly the battery is discharged or charged). Capacity and rate capability can be improved by making materials very small or by incorporating conductive metals into the matrix into the material. The goal of your research is to assess how the amount of phage used in biomineralization affects capacity.

The theoretical capacity of a battery is the quantity of electricity involved for the electro-chemical reaction within the battery. For our Fe(III)-phage batteries, the theoretical capacity is 178 mA*h/g, a value based on the cathode material - FePO4. Using this information, we can calculate the "loading factor" for the Galvanostat to be 54.9 mA/g (theoretical capacity divided by the time used to charge/discharge). This is the amount of current to use for a 10 hour discharge. The discharge time is selected by the researcher. Slower discharge times are better as diffusion of the solvents is increased making it more likely that your battery will reach it's theoretical capacity.

To calculate the current needed to fully charge or discharge your battery, you need to account for the mass of your cathode. The mass of every electrode will be a little different, so the charge/discharge rates will be slightly different. But as an example, if your battery cathode is precisely 1 mg of active material, then to discharge it in 10 hours we'd have to apply a negative current of -54.9 μA.


1 mg active material x 178 mA*h/g x 1 g/1000 mg x 1/10 h = 54.9 μA

It is important to remember note that your cathode consists of more than just the active material. Remember that when you prepared your cathode material you used 70% Fe(III)-phage nanowires, 25% Super P, and 5% PTFE...in addition your Fe(III)-phage nanowires are ~10% phage. To account for this, you need to adjust the weight of your cathode weight by multiplying by 0.63. Be sure to know how this value was determined!

Plot illustrating how the of amount of phosphate influences capacity when phage quantity is held constant.
For a real world example, take a look at your cell phone battery. If you have a typical LiCoO2 battery you will notice that it has a voltage (3.7 V) and a capacity (e.g. 710mA*h for the Motorola MOTORAZR V3r battery). Given that LiCoO2 has a theoretical capacity of 130 mA*h/g, it's possible to back calculate the amount of active material as 5.46 g (try it!). Motorola determined the capacity and voltage for their cell phone batteries by testing them on a Galvanostat. This machine applies either positive or negative current to charge or discharge the batteries, identical to the procedure used to test your battery. By attaching a battery to a Galvanostat and applying a constant current, the battery will charge in a given time interval. By applying a negative current it's possible to discharge the battery in that same amount of time. A discharge graph, such as the one shown here, plots voltage vs. capacity discharged. The flatter the curve the better, since this means voltage remains constant as the battery is used.

Protocols

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